The top plate will experience a friction force to
the left, since it is doing work trying to drag the fluid along
with it to the right. The fluid at the top of the channel will
experience an equal and opposite force (i.e. to the right). Similarly
the bottom plate will experience a friction force to the right,
since the fluid is trying to pull the plate along with it to the
right. The fluid at the bottom of the channel will feel an equal
and opposite force, i.e. to the left. In fluid mechanics, shear
stress, defined as a tangential force per unit area, is used rather
than force itself. Define
(Greek letter "tau") as the
friction force per unit area acting on the fluid, as illustrated
below:
Given: | A block of weight W is sliding down an incline at constant speed V on a thin film of oil of thickness h, as sketched. |
Find: | Speed V as a function of the other variables in the problem |
Solution: | Draw a free body diagram of the block. The forces acting on the block are its weight, W, a normal force, N, due to pressure of the oil on the bottom surface of the block, and a viscous force, Fviscous, due to friction on the bottom of the block. |
Water wets glass | Mercury does not wet glass |